SOLUTION: Sky divers. Bob and Betty simultaneously jump from two airplanes at different altitudes. Bob�s altitude t seconds after leaving his plane is -16t^2 + 6600 feet. Betty�s altitude

Question 280338: Sky divers. Bob and Betty simultaneously jump from
two airplanes at different altitudes. Bob�s altitude
t seconds after leaving his plane is -16t^2 + 6600 feet.
Betty�s altitude t seconds after leaving her plane is
-16t^2 + 7400 feet. Write a polynomial that represents the
difference between their altitudes t seconds after leaving
the planes. What is the difference between their altitudes
3 seconds after leaving the planes?

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Bob(t) = 6600 - 16t^2
Betty(t) = 7400 - 16t^2
---------
Betty(t) - Bob(t) = 800 feet
------------------------
For all values of t, the difference is 800 feet as long as they're in freefall, ignoring air resistance and other physical differences.

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