SOLUTION: Find all real zeros of the polynomial function.
f(x)=-8x^4+648x^2
I just can't seem to figure this one out.
Algebra.Com
Question 27901: Find all real zeros of the polynomial function.
f(x)=-8x^4+648x^2
I just can't seem to figure this one out.
Answer by sdmmadam@yahoo.com(530) (Show Source): You can put this solution on YOUR website!
Find all real zeros of the polynomial function.
f(x)=-8x^4+648x^2
Given f(x)=-8x^4+648x^2 ----(1)
To find all those values of x for which f(x) = 0
Therefore putting
-8x^4+648x^2 = 0
-8x^2(x^2-81) = 0
(-8) cannot be zero
x^2 = 0 implies x= 0
(x^2-81) = 0
implies x^2=81
x = +9 or -9 taking sq root
The fourth degree equation in x has all its roots real
and the real roots are 0,0 (-9) and 9
Note; x= 0 is root of multiplicity 2( that is a root occurring twice)
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