SOLUTION: {{{x^3+x^2-10x-6}}}/x-3
Can you please help me solve this? Thank you.
Algebra.Com
Question 276721: /x-3
Can you please help me solve this? Thank you.
Found 2 solutions by jim_thompson5910, scott8148:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
In order to simplify this, we can use polynomial long division.
So the quotient is and the remainder is 0. This means that or more simply
Note: consequently, this means that (just multiply both sides by )
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
it is like "long division" from grade school
x goes into x^3, x^2 times
x^2 times (x - 3) is (x^3 - 3x^2)
(x^3 + x^2) minus (x^3 -3x^2) is 4x^2 ___ bring down -10x
x goes into 4x^2, 4x times
4x times (x - 3) is (4x^2 - 12x)
(4x^2 - 10x) minus (4x^2 - 12x) is 2x ___ bring down -6
x goes into 2x, 2 times
2 times (x - 3) is (2x - 6)
(2x - 6) minus (2x - 6) is zero ___ no remainder
/x-3 = x^2 + 4x + 2
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