SOLUTION: Perform the indicated divisions. 8x^3 - 6x^2 + 2x ___________ ____ 4x + 1 I am no good at this. I appreciate your help. Thank you.

Algebra.Com
Question 27663: Perform the indicated divisions.
8x^3 - 6x^2 + 2x
________________
4x + 1
I am no good at this.
I appreciate your help. Thank you.

Answer by longjonsilver(2297)   (Show Source): You can put this solution on YOUR website!
ok... long division:

in dividing 2345 by 18, you consider how many 18's go into "2"-000: Answer none.
Now, we extend to think of as "23"-00
--> 18's in 23? answer 1 with 5 left over.

So, now how many 18's go into 545.
--> How many 18's into 5? Answer: zero
Now we extend again
--> how many 18's into 54? answer 3 with no remainder.

And the final 5? that is the final remainder.
--> Complete Answer is 103 and 5/18

We do the exact same process with algebraic expressions.




How many 4x's go into ? Answer is .

is so subtract that from the original, leaving us with --> call this the "new original"

Now repeat the process...
How many times does 4x go into
Answer is -x.

So, is . Now subtract that from the "new original", leaving us with x --> call this the "new original".

Now repeat the process again...
How many times does 4x go into x
Answer is (1/4).

So is . Now subtract this from the "new original", leaving us with (1/4).

This is the end.
Answer to is with remainder (1/4).

The secret is to put the working out under itself, in neat columns, so you can see it all. I cannot do that here :-( However, this website

http://www.rfbarrow.btinternet.co.uk/htmasa2/AlgDiv1.htm

shows the process perfectly.
jon.

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