SOLUTION: Factor completely x^6 - 6x - 16 I factored it to (x^3-8)*(x^3+2) and then to(x-2)*(x^2+2x+4)*(x^3+2) but I don't know how to factor it further. Any help would be appreciated.

SOLUTION: Factor completely x^6 - 6x - 16 I factored it to (x^3-8)(x^3+2) and then to(x-2)(x^2+2x+4)*(x^3+2) but I don't know how to factor it further. Any help would be appreciated.

Question 273924: Factor completely
x^6 - 6x - 16
I factored it to (x^3-8)*(x^3+2) and then to(x-2)*(x^2+2x+4)*(x^3+2) but I don't know how to factor it further. Any help would be appreciated.
Thank you
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
As long as the expression is

and not the

you posted, then you 100% correct. is as far as your expression will factor...

unless you want to push things a bit and consider 2 to be the perfect cube of . Then you could use the sum of cubes pattern on the last factor:

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