SOLUTION: Hi I need help in solving this equation: Divide: (20b^3+12b^2+20b+34)/(4b+4) thanks,

Question 269051: Hi I need help in solving this equation:
Divide:
(20b^3+12b^2+20b+34)/(4b+4)
thanks,
Answer by persian52(161) (Show Source): You can put this solution on YOUR website!
(20b^(3)+12b^(2)+20b+34)/(4b+4)
Factor out the GCF of 2 from each term in the polynomial.
(2(10b^(3))+2(6b^(2))+2(10b)+2(17))/(4b+4)
Factor out the GCF of 2 from 20b^(3)+12b^(2)+20b+34.
(2(10b^(3)+6b^(2)+10b+17))/(4b+4)
Factor out the GCF of 4 from each term in the polynomial.
(2(10b^(3)+6b^(2)+10b+17))/(4(b)+4(1))
Factor out the GCF of 4 from 4b+4.
(2(10b^(3)+6b^(2)+10b+17))/(4(b+1))
Reduce the expression (2(10b^(3)+6b^(2)+10b+17))/(4(b+1)) by removing a factor of 2 from the numerator and denominator.
Answer: (10b^(3)+6b^(2)+10b+17)/(2(b+1))
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