SOLUTION: Help please! State any restrictions on x. And solve for x. 5 over (3x) + 2 over (x^2) equals 7 over (9) denminators in ()

Question 264119: Help please! State any restrictions on x. And solve for x.
5 over (3x) + 2 over (x^2) equals 7 over (9)
denminators in ()
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
State any restrictions on x. And solve for x.
5 over (3x) + 2 over (x^2) equals 7 over (9)
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(5/3x) + 2/x^2 = 7/9
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Multiply thru by 9x^2 to get:
15x + 18 = 7x^2
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Rearrange:
7x^2 - 15x - 18 = 0
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Use Quadratic Formula:
x = [15 +- sqrt(225 - 4*7*-18)]/14
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x = [15 +- sqrt(729)]/14
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x = [15 +- 27]/14
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x = [42/14) or x = [-12/14]
x = 3 or x = -6/7
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Cheers,
Stan H.

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