SOLUTION: Hi, I was wondering if you could give me some help on my homework. The book says rewrite each of the following function rules in an equivalent factored form if possible. 1

Question 258957: Hi,
I was wondering if you could give me some help on my homework.
The book says rewrite each of the following function rules in an equivalent factored form if possible.
1. k(t)=7t^2+14t
2. g(x)=x^2+10x+16
3. j(x)=x^2+10
thank you very much for your help.

Found 2 solutions by asuar010, mathbath:
Answer by asuar010(338) (Show Source): You can put this solution on YOUR website!
k(t)=7t(t+2) all that needed to be done was to factor out what both terms had in common which was the 7t.
g(x)=(x+8)(x+2) they way to do this problem is to think of two numbers that when multiplied give me 16 and added give 10, which are the last and middle terms of the original polynomial.
j(x)=x^2+10, this exercise cannot be factored.
Answer by mathbath(13) (Show Source): You can put this solution on YOUR website!

1. k(t)=7t^2+14t
Simplifying..
k(t) = 7*t*t + 14*t
k(t) = 7*t*t + 7*2*t -->( Because 7 * 2 = 14)
Picking the common no.s
k(t) = 7*t (t + 2*t)
Final Answer:
k(t) = 7t(t+2t)
Similarly..
2. g(x)=x^2+10x+16
g(x) = x^2 + (2x + 8x) + 2*8 -->(splitting 10x and 16)
g(x) = x(x+2)+8(x+2) --> (picking out the common factors)
Final Answer:
g(x) = (x+2)(x+8) --> (picking out the common factors)
3. j(x)=x^2+10 -->This function cannot be factored

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