SOLUTION: I'm trying to find a polynomial for the perimeter and area of a rectangle. n+6 is on the top and n is on the right side.. I came up with n^2+12+36 for the area polynomial and (n

Question 256612: I'm trying to find a polynomial for the perimeter and area of a rectangle. n+6 is on the top and n is on the right side..
I came up with n^2+12+36 for the area polynomial and (n+6)^2+n^2 for the perimeter.. not sure if these are correct though. Please advise. thanks!
Phil
Found 3 solutions by drk, palanisamy, Alan3354:
Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!
Lets start with perimeter formula as

From the given information,. we have

which is

--
Now we have the area formula as

again, from the given, we get

which is

Answer by palanisamy(496)   (Show Source): You can put this solution on YOUR website!
Given the length of the rectangle = n+6
And the width of the rectangle = n
Perimeter = 2(n+6+n) = 2(2n+6) = 4n+12
And Area = (n+6)*n = n^2+6n
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Area = length * width
Area = n*(n+6)
-------------
Perimeter = 2L + 2W
P = 2n + 2n+12
P = 4n+12
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