SOLUTION: I'm really bad at word problems. This one i am lost and i don't get. Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than of the square o

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Question 252543: I'm really bad at word problems. This one i am lost and i don't get.
Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than of the square of the largest number.
I would greatly appreciate the help and in advance saying thank you very much!

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
I'm really bad at word problems. This one i am lost and i don't get.
Find 3 consecutive even numbers

That's , the smallest, , the middle sized, 
and , the largest

where the product of the smaller two numbers

That product is  times , which is 

is 64 less than of the square of the largest number.

That means that that product is equal to the largest number, ,
squared or , with  subtracted from it.  That is, 
that product is equal to 

So it's nothing but the equation:



See? It just takes reading carefully and thinking about what
it really says about those unknown even integers. Can you now solve 
that equation?  If not post again asking how.  The answer is
, so the three consectutive even integers are ,,
and .

And you can easily check it:

the product of the smaller two numbers is 8x10 or 80,
and 80 really is 64 less than 144, which the largest,
12, squared.

Edwin


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