5x - 5 -------------------------------- x² + x + 1 ) 5x³ + 0x² + Mx + N 5x³ + 5x² + 5x ---------------------- -5x² + (M-5)x + N -5x² - 5x - 5 ------------------------- [(M-5)+5]x + (N+5) Remainder = [(M-5)+5]x + (N+5) = 0 [M-5+5]x + (N+5) = 0 Mx + N+5 = 0 The only this can be identically 0 for all values of x is for the coefficient of x to be 0. So M=0, so N+5 = 0 N = -5 Therefore M + N = 0 + (-5) = -5 choice c Edwin