SOLUTION: Can someone please help me with this problem?? Thank you so much in advance!!! Divide: (42b^3 + 9b^2 + 42b + 27) / (6b + 3)

Question 251067: Can someone please help me with this problem?? Thank you so much in advance!!!
Divide:
(42b^3 + 9b^2 + 42b + 27) / (6b + 3)

Answer by JimboP1977(311) (Show Source): You can put this solution on YOUR website!
You need to use algebraic division outlined here
http://www.purplemath.com/modules/polydiv3.htm
The example to follow is 3x^3 � 5x^2 + 10x � 3 by 3x + 1 because this gives a remainder as in your problem.
The answer to your problem is 7b^2-2b+8 + (3/6b+2)
Have a go at the steps and see if you can get the answer. Write back if you need help with the stages.
I will give you the first stage. Divide 6b into 42b^3 gives 7b^2.

RELATED QUESTIONS
I am having so much trouble with 3 problems. I keep doing them over and over and coming... (answered by richwmiller)

divide: (42b^3+16b^2+40b+36)/(6b+4) Thank... (answered by jim_thompson5910)

Divide... (answered by rwm)

can someone please help me with the answer to this problem: (-10xy^3z^2)^3 thank you... (answered by Nate)

can someone please help me with factoring this problem: 8a^2b-2ab thank you so much in... (answered by longjonsilver)

Divide (42b^3+23b^2+32b+41) divided by (6b+5) not sure which is the ans. if at all... (answered by PRMath)

1: t^3 - 2t^2 -63t factor the trinomial 2: (42b^3 + 23b^2 + 38b + 41) / (answered by vleith)

solve this equation: 42b^9-2b^7+48b^3 divided by 6b^3-24b^7 (answered by jsmallt9)

Can someone please help me with this problem: 4a^3+4a^2-3a-3, I need to factor by... (answered by checkley71)