SOLUTION: I am asking this question to compare it with another question: "The length of a rectangle is 6 cm less than twice its width. Find the dimensions of the rectangle if its area is 10

Question 250838: I am asking this question to compare it with another question: "The length of a rectangle is 6 cm less than twice its width. Find the dimensions of the rectangle if its area is 108 cm (squared)."
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 6 cm less than twice its width . . . Since you read width last, it gets the variable first. So, Width = W and length = 2W - 6.
A = LW
108 = (2W-6)*(W)
108 = 2W^2 - 6W
2W^2 - 6W - 108 = 0
divide all by 2.
W^2 - 3W - 54 = 0
(W-9)(W+6) = 0
W = 9 cm
W = -6 cm. This answer you cannot use.
If W = 9cm, then L = 12 cm.

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