SOLUTION: There were 37,000 people at a ball game in Los Angeles. The day's receipts were $262,000. How many people paid $11 for reserved seats and how many paid $6 for general admission?

Question 248653: There were 37,000 people at a ball game in Los Angeles. The day's receipts were $262,000. How many people paid $11 for reserved seats and how many paid $6 for general admission?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
R+G=37,000 OR R=37,000-G
11(37,000-G)+6G=262,000
407,000-11G+6G=262,000
-5G=262,000-407,000
-5G=-145,000
G=-145,000/-5
G=29,000 ANS. FOR THE NUMBER OF GENERAL ADMISSION TICKETS SOLD.
37,000-29,000=8,000 RESERVED SEAT TICKETS SOLD.
PROOF:
11*8,000+6*29,000=262,000
88,000+174,000=262,000
262,000=262,000

RELATED QUESTIONS
Solve the problem. There were 37,000 people at a ball game in Los Angeles. The day's... (answered by Mathtut)

There were 28,000 people at a ball game in Los Angeles. The day's pay receipts were... (answered by vanaynay26)

There were 34,000 people at a ball game in Los Angeles. The day's receipts were... (answered by stanbon)

There were 34,000 people at a ball game in Los Angeles. The day's receipts were... (answered by checkley77)

There were 44,000 people at a ball game in Los Angeles. The day's receipts were... (answered by chessace)

There were 41,000 people at a ball game in Los Angeles. THE day's receipts were $340,000. (answered by stanbon)

There were 32,000 people at a baseball game in Los Angeles. The day's receipts were... (answered by ewatrrr)

It's a word problem, which I have no idea how to setup. I'm thinking it's a system of... (answered by JimboP1977,Alan3354)

Solve the problem using the elimination method. You must write two equations with two... (answered by Fombitz)