SOLUTION: The polynomial equation x(x^2+4)(x^2-x-6)=0. Has how many real roots? We are very rusty on our Algebra skills, and we are reviewing for a mat

Question 24416: The polynomial equation
x(x^2+4)(x^2-x-6)=0. Has how many real roots?
We are very rusty on our Algebra skills, and we are reviewing for a math placement exam, b/c we are returning back to college.
Thanks,
K
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You can apply the zero product principle to this problem: If then either or or both.

and/or and/or
One of the real roots is x = 0
If then and x = +or- so these two roots are:
x = 2i and x = -2i These are not real roots
If then so and These two roots are real.
The real roots are:
x = 0
x = -2
x = 3
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