SOLUTION: What is d^2+3d/ d^2-2d minus -4/d?

Question 243034: What is d^2+3d/ d^2-2d minus -4/d?
Found 2 solutions by checkley77, oberobic:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(d^2+3d)/(d^2-2d)-(-4/d)
d(d+3)/d(d-2)+4/d cancel out the d fron the first fraction
(d+3)/(d-2)+4/d find LCD & add.
[d(d+3)+4(d-2)]/d(d-2)
(d^2+3d+4d-8)/d(d-2)
(d^2+7d-8)/d(d-2)
(d+8)(d-1)/d(d-2) ans.

Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!

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Minus a -4/d is the same as adding it.

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You can factor a 'd' from the numerator and denominator of the first part:

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Then you can 'cancel' d/d because it is just 1.
You can factor a 'd' from the numerator and denominator of the first part:

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Solving any faction, we create a common denominator, which in this case would be:

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Now we simply combine the fractions:

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Can we factor the quadratic in the numerator?
Well, the factors of 8 are 1 * 8 and 2 * 4. We know they are opposite sign because we have -8. And we need them to total 7, which we can do with +8 and -1.

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That's as far as we can go.
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