SOLUTION: (2u^3-13u^2-8u+7)divided by (u-7)
I have the quotient as 2u^2+u-15 with a
remainder of 105
Useing long division
This seems wrong because the reamainder
was 0-105. Please he
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Question 23672: (2u^3-13u^2-8u+7)divided by (u-7)
I have the quotient as 2u^2+u-15 with a
remainder of 105
Useing long division
This seems wrong because the reamainder
was 0-105. Please help me out.
Thank you
Found 2 solutions by venugopalramana, Earlsdon:
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
(2u^3-13u^2-8u+7)divided by (u-7)...YOU CAN USE SHORT DIVISION FOR THIS ...
LET U-7=0...U=7
7....|.......2........-13.......-8..........7
.....|.......0........14........7..........-7
-------------------------------------------------
.....|.......2.........1.........-1.........0
HENCE REMINDER IS ZERO
QUOTIENT IS 2U^2+U-1....
IF YOU SHOW YOUR WORKING , WE CAN TELL WHERE YOU HAVE ERRED.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Hmmm...I get the following when I do the long division:
= with no remainder.
Check: Multiply your divisor by the quotient to see that you get the dividend back.
Simplify the right side.
Which is your original dividend.
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