SOLUTION: I need to factor t^3-8. I have (t-2)(t^2+ + ) I can't figure out the rest can you help me please?

Question 234515: I need to factor t^3-8. I have (t-2)(t^2+ + )
I can't figure out the rest can you help me please?
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
You were given the difference of two cubes.
The general formula for the difference of two cubes is:
a^3 - b^3 = (a - b)(a^2 + ab + b^2 )
Before using the formula, note that 8 must be written as some number to the third power since we are dealing with cubes. We know that 2^3 = 8 because
2 x 2 x 2 = 8.
We can then write your expression as t^3 - 2^3.
Are you with me so far?
We can now use the formula given above.
In the formula, a = t and b = 2.
t^3 - 2^3 = (t - 2)(t^2 + 2t + 4)
Final answer for t^3 - 8 is (t - 2)(t^2 + 2t + 4)

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