SOLUTION: I am supposed to factor the trimonial:
b^2+8b + 16
Is the answer 2 because b^2 + 8b factor out completely, leaving 2 since 8x2=16?
Algebra.Com
Question 234334: I am supposed to factor the trimonial:
b^2+8b + 16
Is the answer 2 because b^2 + 8b factor out completely, leaving 2 since 8x2=16?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
NO the answer is not 2.
What rule allows you to factor out b^2+8b and how does that leave you 2?
------------------------------------------
The proper solution follows:
b^2+8b+16
(b+4)(b+4)
(b+4)^2 ans.
RELATED QUESTIONS
factor the trinomial . Factor out -1 first.
-b^2+8b-12... (answered by ursuchacrass)
b^2+16-8b (answered by jim_thompson5910)
factor... (answered by checkley77)
Can you completely factor out the polynomial 2b^2-8b-3 or is it simply... (answered by jim_thompson5910)
factor.
b^2-8b+15... (answered by stanbon)
factor polynomial completely... (answered by mananth,unlockmath,stanbon)
factor the sum or difference of cubes
8b^5-64B^2
A.8(B^3+2)(B^2+2B-4)... (answered by stanbon)
factor completely... (answered by nerdybill)
can you please help me factor this 2a^2-8b^2+16b-8
I get the following... (answered by KojackDavis)