SOLUTION: divide:
x^2-9/4 /x^2-6x+9/x^-x-6
please show me how to work this out
Algebra.Com
Question 231778: divide:
x^2-9/4 /x^2-6x+9/x^-x-6
please show me how to work this out
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
divide:
x^2-9/4 /x^2-6x+9/x^-x-6
:
Assuming the problem is
----------
:
Invert the dividing fraction and multiply
*
Factor
*
Cancel (x-3) twice; leaving
* (x+2) =
RELATED QUESTIONS
Can someone please show me how to divide this problem?
x^4+6x^2+9
BY... (answered by richwmiller)
(2x+3)/4 + (x-5) / 3 = 3/2
I have done some of this but i have gotten stuck after this (answered by Cromlix)
original problem: 5x^2-30x+40=0
work:
5x^2-30x=-40
x^2-6x=-8... (answered by stanbon,Earlsdon)
1/4=32x-1/x+2 please show me how to work this... (answered by jim_thompson5910,josmiceli)
How do I divide this?
(x^4 + 6x^2 + 9) ÷ (x^2 + 1)
thanks... (answered by poliphob3.14)
Divide... (answered by rfer)
Use factoring to solve the equation
6x^2 + 23x - 18 = 0
I know the choices are... (answered by stanbon)
1. (x+4)/(x)-(2x-5)/(x+1)
2. (2-x)/(2x+6)+ x/(x^2-9)
Could someone help me work... (answered by mananth)
x^4+x^2-6/x^4+6x^2+9 (answered by ikleyn)