SOLUTION: find the equation of the line passing through (6,-4)and perpendicular to the line whose equation is 3x-y-5=0 write the answer in slope-intercept form.

Question 227552: find the equation of the line passing through (6,-4)and perpendicular to the line whose equation is 3x-y-5=0 write the answer in slope-intercept form.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Thru (6,-4)and perpendicular to 3x-y-5=0
-y=-3x+5
y=3x-5 This line has a slope=3. (red line)
The perpendicular line will have a slope=-1/3.
-4=-1/3*6+b
-4=-6/3+b
b=-4+6/3
b=-4+2
b=-2 The y intercept.
y=-x/3-2 equation for the perpendicular line thru (6,-4). (green line)
(graph 300x300 pixels, x from -6 to 6, y from -6 to 6, of TWO functions 3x -5 and -x/3 -2).
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