SOLUTION: 25y^2+20y+4=0

Question 225834: 25y^2+20y+4=0
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!

Step 1. Use quadratic formula given below to solve problem.

where a=25, b=20 and c=4.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=0 is zero! That means that there is only one solution: .
Expression can be factored:

Again, the answer is: -0.4, -0.4. Here's your graph:

Step 2. ANSWER: Solutions are -0.4 and -0.4

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
http://www.FreedomUniversity.TV

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