SOLUTION: Can anyone help with this, I am lost! Graph the parabola, locate vertex, axis of symmetry and intercepts. f(x) = 7x - 5x^2 I tried: x(7-5x) -x(5x-7) Or: -5x^2 + 7x [-5x

Question 22413: Can anyone help with this, I am lost!
Graph the parabola, locate vertex, axis of symmetry and intercepts.
f(x) = 7x - 5x^2
I tried:
x(7-5x)
-x(5x-7)
Or:
-5x^2 + 7x
[-5x^2 + (7/2)^2] + (7/2)^2
-(5x^2 - 7x - 49/2) + 49/2
Now I'm lost!
Can anyone help?
Thanks!
Sandy
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
There are many ways to do this and you should do it with the tools
you are currently studying.
One way to attack the problem is to find the x-intercepts.
Let y=0, then 7x-5x^2 = 0
x(7-5x)=0
x=0 and x=7/5 are the x-intercepts.
The axis of symmetry is half way between these values.
So axis of symmetry is x=7/10.
You can find the vertex by finding the y value when x=7/10.
Cheers,
Stan H.
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