SOLUTION: 3^9 . (x^2 y)^-2/ 3^3 . x^-4 y
answer: 3^6/y^3 or 729/y^3
how did my math book get this answer and can anyone explain by defintions and rules for exponents i got as f
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Question 219489: 3^9 . (x^2 y)^-2/ 3^3 . x^-4 y
answer: 3^6/y^3 or 729/y^3
how did my math book get this answer and can anyone explain by defintions and rules for exponents i got as far as 3^6 power by quotient rule but then i got stuck by the rest
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
^{-2}}{3^3\cdot x^{-4}y})
Start with ^n = a^{mn})
and 
, so:
}y^{\left(1\cdot -2\right)}}{3^3\cdot x^{-4}y}\ =\ \frac{3^9\cdot x^{-4}y^{-2}}{3^3\cdot x^{-4}y})
Next use 
, so:
Next use 
and 
, so:
Finally, use 
, so:
John
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