SOLUTION: Please help me figure this problem out. The directions state to find each product.
(2/3y - 1/2)^2
Algebra.Com
Question 217873: Please help me figure this problem out. The directions state to find each product.
(2/3y - 1/2)^2
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
2/3y-1/2
2/3y-1/2 multiply
-----------------
4y^2/9-1/2*2y/3-1/2*2y/3+1/4
4y^2/9-2y/6-2y/6+1/4
4y^2/9-4y/6+1/4
[(4*4y^2-6*4y+9)]/36
[(16y^2-24y+9)]/36
(4x-3)(4x-3)/36 ans.
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