SOLUTION: very confused about these two questions solve for x x(x - 5) =4 and (x +2))x-3)(x-6)=0 thanks for your help.

Question 21675: very confused about these two questions
solve for x
x(x - 5) =4
and
(x +2))x-3)(x-6)=0
thanks for your help.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1st: x^2-5x=4
x^2-5x-4=0
Use the quadratic formula to get:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=41 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 5.70156211871642, -0.701562118716424. Here's your graph:

2nd:
(x+2)(x-3)(x-6)=0
For this product to be zero one of these factors must be zero, so:
x+2=0 or x-3=0 or x-6=0
So, x=-2 or x=3 or x=6
Cheers,
Stan H.

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