Find all real and complex zeros for
P: 1,3,5,15
Q:1
Since the function as you given it has no rational roots, I'm going to guess that you have a typo and . If this is wrong, then stop reading (and you may need to repost your question).
With this h(x) we can find that -3 is a rational root. To illustrate I'll use synthetic division because it will also show how to factor h(x):
-3 | 1 -1 -7 15
---- -3 12 -15
-------------------
1 -4 5 0
The remainder, 0, tells us that h(-3) = 0. So -3 is a root of h(x). And if -3 is a root of h(x), then (x+3) is a factor of h(x). And the other factor is found in the numbers in front of the reaminder above, "1 -4 5", which translates into .
So . The other roots for h(x) will come from the roots of . This is a quadratic. Since it will not factor we'll use the quadratic formula:
For our expression, a = 1, b = -4 and c = 5. Substituting these into the formula we get:
Simplifying...
With the negative in the square root, we will have complex roots.
The 2's cancel leaving:
So our three roots are: -3, 2+i and 2-i