SOLUTION: need help to find the equation of the line which contains the point (5,-2)and has slope negative two fifths.

Question 212520: need help to find the equation of the line which contains the point (5,-2)and has slope negative two fifths.

Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Need help to find the equation of the line which contains the point (5,-2)and has slope negative two fifths.

Step 1. The slope m is given as

Step 2. Let (x1,y1)=(5,-2) or x1=5 and y1=-2 . Let other point be ((x2,y2)=(x,y) or x2=x and y2=y.

Step 3. Now we're given . Substituting above values and variables in the slope equation m yields the following steps:

Step 4. Multiply x-5 to both sides to get rid of denominator on right side of equation.

Step 5. Now multiply 5 to both sides of equation to get rid of denominator on left side of equation.

Step 6. Now multiply everything out and solve for y

Subtract 10 from both sides to isolate y

Divide by 5 to get y

Note: the above equation can be rewritten as

And the graph is shown below which is consistent with the above steps.

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .

X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 0/2 = 0.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 0/5 = 0.
Slope is -2/5 = -0.4.
Equation in slope-intercept form: y=-0.4*x+0.

I hope the above steps were helpful. Good luck in your studies!

Respectfully,
Dr J

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.

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