SOLUTION: how is this problem factored. 3xy^2+11xy-20x

Question 209408: how is this problem factored.
3xy^2+11xy-20x
Found 2 solutions by RAY100, stanbon:
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
3xy^2 +11xy -20x,,,,if we factor common term (x)
.
x(3y^2 +11y-20)
.
looking at second factor
.
last term is (-), therefore factors have different signs, and second term is difference of factors
.
Middle term is (+), therefore, largest factor is (+)
.
factor of 1st term is,,, 1*3
.
factors of last term are,,,1*20,,2*10,,,4*5
.
x(3y-4)(y+5),,,,,answer
.
check by multiplying factors
.
(3xy -4x)(y+5)
.
3xy^2 +15xy -4xy -20x
.
3xy^2 +11xy -20x,,,,,,,ok
.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how is this problem factored.
3xy^2+11xy-20x
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Think of two numbers whose product is 3*-120 = -60
and whose sum or difference is 11
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The numbers are 15 and 4
-------------------------------
Rewrite the problem:
x(3y^2 + 11y - 20)
x(3y^2 + 15y - 4y - 20)
x(3y(y+5)-4(y+5))
x(y+5)(3y-4)
======================
Cheers,
Stan H.
Reply to stanbon@comcast.net
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