SOLUTION: use partial functions to decompose the expression 17n-23 / 4n^2+23n-6

Question 209055: use partial functions to decompose the expression 17n-23 / 4n^2+23n-6
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
use partial functions to decompose the expression 17n-23 / 4n^2+23n-6
----------------------
Factor the denominator to get (n+6)(4n-1)
--------------------------
Set up the partial fractions:
A/(n+6) + B/(4n-1)
------------------------
Simplify:
[A(4n-1) + B(n+6)]/(4n^2+23n-6)
---
[4An + Bn -A + 6B]/ denominator
---
= [ (4A+B)n + (-A+6B)]/denom
---
Equate to the original fraction to see that
4A+B = 17
-A+6B = -23
--------------------
Solve this system to get:
A = 5
B = -3
=============================
Cheers,
Stan H.
Reply to stanbon@comcast.net or algebra.com

RELATED QUESTIONS
decompose the expression (17n-23)/ (4n^2+23n-6) into partial... (answered by solver91311)

decompose the expression (17n-23)/(4n^2+23n-6) into partial... (answered by solver91311)

partial fraction decomposition; use the partical fraction decomposition to "decompose"... (answered by venugopalramana)

Simplify the rational expression. (4n^2 -11n -3) / (5n^2 - 17n... (answered by algebrahouse.com)

I want to find the value of a, b, and c so that i can decompose it into partial functions (answered by ankor@dixie-net.com)

find the value of a, b, and c so that i can decompose it to partial functions (3x... (answered by ankor@dixie-net.com)

i need help on one question you are to factor this quadratic expression... (answered by Alan3354,stanbon)

I'm having a rough day! Here's another mind boggler that the book doesn't explain the... (answered by rapaljer)

Decompose into partial fractions:... (answered by Fombitz)