SOLUTION: Let f(x)=3/4x-1/2, A) find f(2)+f(-2) and B) find the zero of f(x). So far, I did 3/4(2)-1/2. Then I did 3/4(-2)-1/2. I got 1 and -2 so I added them and got -1 for A). But

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Let f(x)=3/4x-1/2, A) find f(2)+f(-2) and B) find the zero of f(x). So far, I did 3/4(2)-1/2. Then I did 3/4(-2)-1/2. I got 1 and -2 so I added them and got -1 for A). But      Log On


   

Question 208153: Let f(x)=3/4x-1/2, A) find f(2)+f(-2) and B) find the zero of f(x).
So far, I did 3/4(2)-1/2. Then I did 3/4(-2)-1/2. I got 1 and -2 so I added them and got -1 for A).
But for B), I don't quite understand what that section of the question is asking
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
A) Good Job. You just need to add 1 to -2 to get -1. So f(2)+f(-2)=-1


B) The zero of f(x) is simply the value of 'x' (not necessarily equal to zero) that when you plug in to f(x), you'll get zero. In other words, the value 'k' is a zero if f%28k%29=0

What this means is that you now plug in f%28x%29=0 into f%28x%29=%283%2F4%29x-1%2F2 to get 0=%283%2F4%29x-1%2F2. From there, just solve for 'x' to find the zero.