SOLUTION: Can someone help me solve these equations:
(w+3)^-1/3=1/3 and
(x+2)^3/2=-1
I have no clue where to start.
Algebra.Com
Question 208136This question is from textbook Elementary and intermediate algebra
: Can someone help me solve these equations:
(w+3)^-1/3=1/3 and
(x+2)^3/2=-1
I have no clue where to start.
This question is from textbook Elementary and intermediate algebra
Found 2 solutions by Alan3354, ankor@dixie-net.com:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
(w+3)^-1/3=1/3
Raise both sides to the 3rd power
(w+3)^-1 = 1/27
Invert
w+3 = 27
w = 24
--------
(x+2)^3/2=-1
Square both sides
(x+2)^3 = 1
x+2 = 1
x = -1 (ignoring the complex number solutions)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
:
Reciprocal gets rid of the negative exponent
:
Multiply both side by 3
:
Cube both sides:
:
27 = w + 3
:
w = 24
:
:
Check solution on calc: enter = .333
;
;
;
= -1
:
Square both sides
= +1
:
Find the cube root of both sides:
x + 2 = 1
:
x = 1 -2
x = -1
The problem here is if you substitute -1 for x in the original equation,
you get +1 not -1, so there is no solution here
RELATED QUESTIONS
Write 64^(1/3)=x in logarithmic form. Please help me I have no clue where to start. Thank (answered by rothauserc)
1 1/15 + 3 3/10 - 2 4/5 = ??
Can someone help me with this please, I really have no idea (answered by edjones)
Find an expression that represents it's perimeter.
3/4x,1/x^2, and 5/x^2
I have no... (answered by ankor@dixie-net.com)
solve;
1/(x-3) + 1/(x+3)=2/(x^2-9)
can someone help me to set this problem up to... (answered by htmentor,Gogonati)
Can someone tell me what I'm supposed to do? I don't get it. I'm supposed to find the... (answered by josgarithmetic,lwsshak3)
Please can someone help? I have no idea where to start, and please show me how u got the... (answered by Alan3354)
Fractions are not my strong suit..and I have no clue where to start to solve this...i... (answered by ccs2011)
solve and check:
3/y= 1/2 + 1/2y
I have no clue where to begin for this problem,... (answered by woolybear)
I am trying to solve the following equations but I am having trouble.
1.... (answered by jim_thompson5910)