SOLUTION: I don't know how to do this problem without a book to see how to do it. Can you help me please. I am supposed to figure out the GCF first. Here is the problem. 5y^5+31y^4+6y^3

Question 207564: I don't know how to do this problem without a book to see how to do it. Can you help me please. I am supposed to figure out the GCF first. Here is the problem.
5y^5+31y^4+6y^3
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
figure out the GCF first. Here is the problem.
5y^5+31y^4+6y^3
----
5,31, and 6 have no common factor other than "1":
y^5,y^4, and y^3 have a common factor of y^3
--------------
Factor out the common factor to get:
y^3[5y^2 + 31y + 6]
---
Factor the binomial:
= y^3[5y^2 +30y + y + 6]
---
= y^3[5y(y+6)+ (y+6)]
---
=y^3(y+6)(5y+1)
====================
Cheers,
Stan H.
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