SOLUTION: Divide: (4x^3 + 8x)/(3x) / (4x^2 + 8)/(6x^2)
Algebra.Com
Question 207236: Divide: (4x^3 + 8x)/(3x) / (4x^2 + 8)/(6x^2)
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
[(4x^3 + 8x)/(3x)] / [(4x^2 + 8)/(6x^2)]
[(4x^3 + 8x)/(3x)] * [(6x^2)/(4x^2 + 8)]
[(4x(x^2 + 2))/(3x)] * [(3x*2x)/(4(x^2 + 2))]
x * 2x
2x^2
Answer:
[(4x^3 + 8x)/(3x)] / [(4x^2 + 8)/(6x^2)] = 2x^2
RELATED QUESTIONS
Divide... (answered by atif.muhammad)
Divide this trinomial... (answered by Earlsdon)
may you please help me sovle these problems?
8x^2 - 6x - 7 divide 4x + 3
3x^2 - x - (answered by ikdeep)
please combine like terms in each of the following...
10x^3+6x^2+4x-8x^3+2x^2-3x... (answered by fractalier)
Divide {{{ x^3 - 4x^2 + 6x - 4... (answered by ewatrrr)
simplify... (answered by funmath)
4X-(6X+1)<=8X +... (answered by jim_thompson5910)
4X-(6X+1)<=8X +... (answered by MathLover1)
8x^3(-4x^2+6x-7)= (answered by tommyt3rd)