Factor (f+4)(2f-3) + (f+4)(f+4) completely



Observe the two factors I've colored red



(f+4)(2f-3) + (f+4)(f+4)



You can factor out that red factor (f+4) because it is common to

both terms.  That will leave the two black factors inside the blue

brackets:



(f+4)[(2f-3) + (f+4)]



Now simplify by removing parentheses inside the blue brackets



(f+4)[2f-3+f+4]



(f+4)[3f+1]



Change the blue brackets to black parentheses and color the red 

factor black:



(f+4)(3f+1)



Edwin

AnlytcPhil@aol.com



  

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