SOLUTION: Divide (5x^7-3x^4+2x^2-10x+2)/(x^2-x+1)
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Question 204951: Divide (5x^7-3x^4+2x^2-10x+2)/(x^2-x+1)
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Normally we should try to factor, and cancel common multiplies ,but thr denominator is not realistic to that approach.
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before we start to divide polynomials remember to "fill" all the powers
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Remember division algorithm is just, divide, multiply, subtract, bring down, and repeat,,,,,,,(pls excuse the commas used to hold place)
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.,,,,,,,,,,,,,,,,,,,,,,,,,,5x^5 + 5x^4 +0x^3 -8x^2 -8x +2
.,,,,,,,,,,,_____________________________________________
(x^2 -x+1) [ 5x^7 +0 x^6 +0x^5 -3x^4 +0x^3 +2x^2 -10x +2
,,,,,,,,,,,,-(5x^7 -5x^6 +5x^5)
,,,,,,,,,,,,,,_________________
,,,,,,,,,,,,,,,,,,,5x^6 -5x^5 -3x^4
,,,,,,,,,,,,,,,,,,-(5x^6 -5x^5 +5x^4)
,,,,,,,,,,,,,,,,,,,___________________
,,,,,,,,,,,,,,,,,,,,,,,,,0x^5 -8x^4 +0x^3
,,,,,,,,,,,,,,,,,,,,,,,-(0x^5 +0x^4 +0x^3)
,,,,,,,,,,,,,,,,,,,,,,,,__________________
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,-8x^4 +0x^3 +2x^2
,,,,,,,,,,,,,,,,,,,,,,,,,,,,-(-8x^4 +8x^3 -8x^2)
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,___________________
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,-8x^3 +10x^2-10x
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,-(-8x^3 + 8x^2 -8x)
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,___________________
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,+2x^2 -2x +2
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,-(2x^2 -2x +2)
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,______________
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,0
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to check, multiply quotient by divisor to get dividend,,,ok
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