SOLUTION: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food?

SOLUTION: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food?

Algebra.Com

Question 204596: If four out of five doctors prefer fast food,
then at a convention of 445 doctors, how many prefer fast
food?

Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!

4 out of 5 or 4/5th or 80% of the doctors prefer fast food, so
80% of 445=445*0.8=356---number of doctors that prefer fast food
Hope this helps----ptaylor
RELATED QUESTIONS
. Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by stanbon)

Fast Food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by nerdybill)

Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by checkley77)

Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by dabanfield)

If four out of five doctors prefer fast food, then at a convention of 445 doctors how... (answered by ewatrrr)

If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by checkley71,stanbon)

Please help me If four out of five doctors prefer fast food,then at a convention of 445... (answered by jim_thompson5910)

If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by stanbon)

If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by rfer)