SOLUTION: Janet invested $26,000, part at 6% and part at 3%. If the total interest at the end of the year is 1,080, how much did she invest at 6%?

SOLUTION: Janet invested $26,000, part at 6% and part at 3%. If the total interest at the end of the year is 1,080, how much did she invest at 6%?

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Question 203687: Janet invested $26,000, part at 6% and part at 3%. If the total interest at the end of the year is 1,080, how much did she invest at 6%?
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
let x = 6% part= $10000
let 26000-x= 3% part= $16000
.06x+.03(26000-x)=1080
.06x+780-.03x=1080
.03x=300
x=10000
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