SOLUTION: Hi! After two hours of trying to figure out this problem, I turn to you for help. Can you please see if you can help me? I'd really appreciate it. Instructions: Factor the pol

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: Hi! After two hours of trying to figure out this problem, I turn to you for help. Can you please see if you can help me? I'd really appreciate it. Instructions: Factor the pol      Log On

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 Algebra: Polynomials, rational expressions and equations Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Polynomials-and-rational-expressions Question 201649This question is from textbook Algebra for college students : Hi! After two hours of trying to figure out this problem, I turn to you for help. Can you please see if you can help me? I'd really appreciate it. Instructions: Factor the polynomial completely using substitution method. ( 2w – 3 )² - 2 (2w – 3 ) - 15 This is as far as I got. Let a = 2w - 3 Factors of -15 are -3, 5 and -5, 3. So (a² - 2a - 15 (a + 3 ) ( a - 5 ) a² + 3a + - 5a - 15 a² - 2a - 15 Replace a with 2w - 3 and you have ( 2w - 3 + 3 ) ( 2w - 3 - 5) Now I am lost! I am ending up with 4w² and I don't want that! And the rest, I just can't figure out. If you can help, that would be super and I would be grateful. Thanks!This question is from textbook Algebra for college students Answer by jim_thompson5910(28595)   (Show Source): You can put this solution on YOUR website!You're doing great, you just need to combine like terms to get So factors to