SOLUTION: Please help! I have tried every way possible and cannot figure these out! #70) b^4+13b^2+36=0 #30) -3x^2-2x-5=0 #42) 9m^2+16=24mn Thank you in advance for your he

Question 201277: Please help! I have tried every way possible and cannot figure these out!
#70) b^4+13b^2+36=0

#30) -3x^2-2x-5=0

#42) 9m^2+16=24mn

Thank you in advance for your help!

Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!

b = 3i, -3i, 2i, -2i
http://www77.wolframalpha.com/input/?i=+b^4%2B13b^2%2B36%3D0

Use this URL --> http://www.algebra.com/algebra/homework/quadratic/quadratic.solver

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -56 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -56 is + or - .

The solution is

Here's your graph:

x=5/3 and 1

I am guessing you left off an n^2

m=4/3
http://www77.wolframalpha.com/input/?i=9x^2-24xy%2B16y^2%3D0

RELATED QUESTIONS
I am stumped...I can not figure these two problems out for the life of me...can someone... (answered by Edwin McCravy)

x = (3x-5) 2 4 I have tried every thing and cant figure it out... (answered by ichudov)

b^4+13b^2+36=0 (answered by Earlsdon)

b^4 + 13b^2 + 36 =... (answered by RAY100)

b^4 + 13b^2 + 36 =... (answered by checkley77)

70.) Find all real and imaginary solutions. b^4+13b^2+36=0 (answered by edjones)

Solve: 1) 12b - 8 _< 13b + 9 I have tried this about 4 times and can not figure it... (answered by Earlsdon)

__ + ( __ / __) x __ = 24 Where do the numbers 2, 8, 4 and 16 go in this equation to... (answered by jim_thompson5910)

solve for b where b^4 +13b^2 + 36 =... (answered by mananth)