SOLUTION: 1. X^2+12x+32/X+4*3/x+8
2. 21x^2z^3/6y^3/7xz^3/2y^4
Please help me out.
April
Algebra.Com
Question 200650: 1. X^2+12x+32/X+4*3/x+8
2. 21x^2z^3/6y^3/7xz^3/2y^4
Please help me out.
April
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
X^2+12x+32/X+4*3/x+8
If you mean
=
One step at a time, cancel the (x+4) terms.
=
Cancel the (x+8)'s
= 3
-----
2. 21x^2z^3/6y^3/7xz^3/2y^4
Is it 21x^2z^3/6y^3 divided by 7xz^3/2y^4 ??
Reduce it some first.
21x^2z^3/6y^3 divided by 7xz^3/2y^4
=
Invert the 2nd fraction and multiply
=
You can either multiply, then cancel, or cancel some terms here.
I'll multiply first.
=
= xy
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