SOLUTION: find the values of a, b,c, and d that make the equation true. (4t^3-at^2-2bt+5)-(ct^3+2t^2-6t+3) = t^3-2t+d

Question 198237This question is from textbook algebra and trigonometry
: find the values of a, b,c, and d that make the equation true.
(4t^3-at^2-2bt+5)-(ct^3+2t^2-6t+3) = t^3-2t+d This question is from textbook algebra and trigonometry

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.

Distribute

Combine like terms.

Group like terms.

Factor out the respective GCFs from each group

Since the coefficient of on the left side is and on the right side is 1, this means that we know that

Because the coefficient for on the left is . However, there is no on the right. So this means that the coefficient of on the right is 0. So

Finally, the coefficients for the "t" terms on the left and right sides are and respectively. So this means that

Take note that the only constants on the left and right sides are "2" and "d". So we know that or

So all you need to do is solve the equations:

To find the values of 'a', 'b', and 'c'. I'll let you do that.

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