SOLUTION: __4__ +1= _2c_
3(c+4) c+4
Algebra.Com
Question 196695: __4__ +1= _2c_
3(c+4) c+4
Found 2 solutions by ankor@dixie-net.com, RAY100:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Assume it's:
:
+ 1 =
:
Multiply ea term by 3(c+4); results
4 + 3(c+4) = 3(2c)
:
4 + 3c + 12 = 6c
:
4 + 12 = 6c - 3c
:
16 = 3c
c =
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
2 4 c +1 = 1 2 c + 3(c+4) c + 4
.
c=i
.
Reasoning is cumulative, 12c +_2c =_4c resulted in 12c+12c +24c,,,
substituting and collecting terms resulted in 3c^2 =-1, or c=i
.
24(i) +1 = 12(i) +3(i)^2 +12(i) +4
.
checking
.
24i +1 = 12i +3(-1) +12i +4
.
24 i +1 = 24i -3 +4 = 24i +1,,, ok
RELATED QUESTIONS
4(c+3)=2c (answered by vleith)
5(c-4)-2c=1 (answered by shweta)
-c^(2/3)(c^(1/3)+2c^(4/3)) (answered by Tatiana_Stebko)
2c-5=c+4 (answered by ReadingBoosters)
6{[3(c-4)+19]-[3(2c-3)+1]} (answered by satiq,richwmiller)
2c-6^3=c+7^4
(answered by Alan3354)
3/(4c+2)-(c-4)/(2c^2+c)-5/6c (answered by rmromero)
Find each product.
(2c - 3) (2c + 4)(2c - 1) (answered by stanbon)
2c+4+c=40
3c+4=40
-4=-4
3c=44
44/3... (answered by jesymae)
c-5d=2... (answered by monika_p)