SOLUTION: Extraneous Solution
Question: 5/y-3 = y+7/2y -6 + 1 LCD is 2(y-3)?
2(y-3)* 5/y-3= y+7/2y-6*2(y-3 + 1 * 2(y-3)
I'm stuck. I don't think I have the correct LC
Algebra.Com
Question 194427: Extraneous Solution
Question: 5/y-3 = y+7/2y -6 + 1 LCD is 2(y-3)?
2(y-3)* 5/y-3= y+7/2y-6*2(y-3 + 1 * 2(y-3)
I'm stuck. I don't think I have the correct LCD.
where did I go wrong? Thank You for your help.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Question: 5/(y-3) = (y+7)/(2y-6) + 1 LCM is 2(y-3)?
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Multiply thru by the LCM to get:
5(2) = (y+7) + 2(y-3)
10 = 3y +1
y = 3
===========
Cheers,
Stan H.
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