SOLUTION: (4a2-5a+1) divided by (6a2-7a+2)
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(a2+a-2) 2a2+3a-2
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Question 193706: (4a2-5a+1) divided by (6a2-7a+2)
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(a2+a-2) 2a2+3a-2
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Please review our interpretation of the problem carefully,,to be sure we solved your problem
,
we are going to factor all trinomials,
and then revise form from,,(a/b)/(c*d),,,to, (a/b)*(d/c), where d=1
and then simplify
,
this gives us
,
((4a-1)(a-1)/(2a-1)(3a-2) )*(1/( (a-1)(a+2)(2a-1)(a+2)))
,
canceling (a-1) in num and den,,,and simplying,,
,
(4a-1) / ( (2a-1)^2 * (a+2)^2 * (3a-2) )
please double check,,,thanks
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