# SOLUTION: 36.) Two positive numbers differ by 11, and their square roots differ by 1. Find the numbers. Solve by any method. 8.) x(x + 1) = 12 Find the complex solutions to the

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: 36.) Two positive numbers differ by 11, and their square roots differ by 1. Find the numbers. Solve by any method. 8.) x(x + 1) = 12 Find the complex solutions to the      Log On

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 Question 193453: 36.) Two positive numbers differ by 11, and their square roots differ by 1. Find the numbers. Solve by any method. 8.) x(x + 1) = 12 Find the complex solutions to the quadratic equations 12.) x^2+6x+10=0Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!36) try 36, and 25 8) x(x+1)=12 x^2+x-12=0 (x+4)(x-3)=0 x= 3,-4 check 3(4)=12 ok -4(-3)=12,,ok 12) x^2+6x+10=0 use quadratic formula a=1,b=6,c=10 x= ( -6=/-sqrt(6^2-4(1)(10))/2(1) x= (-6+/- sqrt(36-40))/2 x=-3=/-i check (-3+i)^2+6(-3+i)+10=0 9+i^2-6i+6i-18+10=0 but i^2=-1 8-18+10=0,,,,ok