SOLUTION: (2 over b-3 ) - (7 over b^2-3b)
Algebra.Com
Question 192851: (2 over b-3 ) - (7 over b^2-3b)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(2 over b-3 ) - (7 over b^2-3b)
------------------
2/(b-3) - 7/(b(b-3))
lcd = b(b-3)
= [2b]/lcd - 7/lcd
= [2b - 7]/lcd
= [2b-7]/[b(b-3)]
==========================
Cheers,
Stan H.
RELATED QUESTIONS
What is the quotient of b^3+4b^2-3b+126 over... (answered by nycsub_teacher)
How do I solve the quotient of b^3+4b^2-3b+126 over... (answered by Mathtut)
It's (3b over 4) minus (1 over 5) = (b over 2) i wanna solve and make b the... (answered by jsmallt9)
divide... (answered by josgarithmetic,MathTherapy)
Divide:... (answered by stanbon,algebrahouse.com)
y=radical sign over 3a^3+3b find the value of y where a=2 and... (answered by tutorcecilia)
3/a + 4 over 5 - 2/b
Simplify. I worked it out to= 4ab + 3b over 5ab - 2a
Am I... (answered by edjones)
b plus 2 over 3 = 2
(answered by colliefan)
-3b/b-2 =... (answered by fractalier)