SOLUTION: This is quadratic equation that I tried on my own. x^2 - 36 = 0 (x+6)(x-6) Am I finished or close? Thank You

SOLUTION: This is quadratic equation that I tried on my own. x^2 - 36 = 0 (x+6)(x-6) Am I finished or close? Thank You

Algebra.Com

Question 192465: This is quadratic equation that I tried on my own.
x^2 - 36 = 0
(x+6)(x-6) Am I finished or close?
Thank You
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
This is quadratic equation that I tried on my own.
x^2 - 36 = 0
(x+6)(x-6) Am I finished or close?
You're close.
(x+6)*(x-6) = 0
Either x+6 = 0, so x = -6
Or x-6 = 0, so x = +6

RELATED QUESTIONS
could you please help me solve this equation x+ 9/x >(or equal) 6 (it is only the 9... (answered by greenestamps,ikleyn)

Please Help. I have a textbook and it takes me through the steps on what I need to do,... (answered by Fombitz)

I have tried to solve the below equation and would to verify that I am correct in my... (answered by Alan3354)

This is a problem off of the practice equation problems from this site. I started to work (answered by Cintchr,Earlsdon)

This is multiplying binomials mentally, my problem is (x+5)(x+2), when I solved it, I got (answered by vleith)

OMG math is killing meeeeeeeee!!!!!!!! :( please solve this for me will you?? As x... (answered by josgarithmetic)

Here are 3 equations that I need you to check my answers on: #1) Solve this equation... (answered by Fombitz)

Please solve the equation y=x^2+4x-6 for the variable x. I have tried to find the x... (answered by josgarithmetic)

Hello I am working with the Descartes rule of signs. I am supposed to discuss the... (answered by stanbon)