# SOLUTION: 9c^2-121 factor completely. I have no idea where to start.

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 192028: 9c^2-121 factor completely. I have no idea where to start.Found 2 solutions by scott8148, RAY100:Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!this is the difference of two squares ___ two perfect squares with a minus in between the square root of 9c^2 is 3c the square root of 121 is 11 the factors are (3c+11)(3c-11) the difference in the signs results in the middle term of the FOILed product being zero (try it!) Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!factoring is recognition of patterns a^2-B^2 = (a+b) (a-b) 9C^2 -121= (3c)^2 -(11)^2= (3c+11)(3c-11) checking by foil (3c+11)(3c-11) 9c^2 -33c+33c-121= 9c^2-121