SOLUTION: solving a polynomial equation.
4y^3-7y^2-16y+28=0
Algebra.Com
Question 189794: solving a polynomial equation.
4y^3-7y^2-16y+28=0
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
4y^3-7y^2-16y+28=0
y^2(4y-7)-4(4y-7)=0
(y^2-4)(4y-7)=0
(y+2)(y-2)(4y-7)=0
y=-2, y=2, y=7/4
.
Ed
RELATED QUESTIONS
factor polynomial... (answered by dabanfield)
Find the specific standard equation for:... (answered by lwsshak3)
solving a polynomial equation... (answered by jim_thompson5910)
Factor
4y^2 + 16y + 7 =... (answered by josgarithmetic)
separately(a) identify the conic and (b) give its center for each equation... (answered by Mathtut)
Solve... (answered by jim_thompson5910)
4y^2-16y-128 (answered by mananth,richwmiller)
graph the hyperbola with the following equation.... (answered by Alan3354)
solving a polynomial equation... (answered by jim_thompson5910)